What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)? (5 points) y = 4x − 2 y = 2x − 4 y = −3(x − 4) y = 3(x + 4)

For this case we have that by definition, the point-slope equation of a line is given by:[tex]y-y_ {0} = m (x-x_ {0})[/tex]We have the following points:[tex](x_ {1}, y_ {1}) :( 2,6)\\(x_ {2}, y_ {2}) :( 4,0)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0-6} {4-2} = \frac {-6} {2} = -3[/tex]We chose a point:[tex](x_ {0}, y_ {0}) :( 4,0)[/tex]Substituting in the equation we have:[tex]y-0 = -3 (x-4)\\y = -3 (x-4)[/tex]Finally, the equation is: [tex]y = -3 (x-4)[/tex]Answer:OPTION C